-16t^2+82t=0

Solution for -16t^2+82t=0 equation:

-16t^2+82t=0

a = -16; b = 82; c = 0;
Δ = b2-4ac
Δ = 822-4·(-16)·0
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-82}{2*-16}=\frac{-164}{-32}
=5+1/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+82}{2*-16}=\frac{0}{-32}
=0
$